Materials Data on Nd(SiPt)2 by Materials Project
Nd(PtSi)2 crystallizes in the tetragonal I4/mmm space group. The structure is three-dimensional. Nd2+ is bonded to eight equivalent Si4- atoms to form NdSi8 hexagonal bipyramids that share corners with sixteen equivalent PtSi4 tetrahedra, edges with four equivalent NdSi8 hexagonal bipyramids, edges with eight equivalent PtSi4 tetrahedra, and faces with four equivalent NdSi8 hexagonal bipyramids. All Nd–Si bond lengths are 3.24 Å. Pt3+ is bonded to four equivalent Si4- atoms to form PtSi4 tetrahedra that share corners with eight equivalent NdSi8 hexagonal bipyramids, corners with four equivalent PtSi4 tetrahedra, edges with four equivalent NdSi8 hexagonal bipyramids, and edges with four equivalent PtSi4 tetrahedra. All Pt–Si bond lengths are 2.49 Å. Si4- is bonded in a 9-coordinate geometry to four equivalent Nd2+, four equivalent Pt3+, and one Si4- atom. The Si–Si bond length is 2.41 Å.