Materials Data on NbTe7Br5O by Materials Project
NbOBr4(Te)3Te4Br crystallizes in the orthorhombic Pcca space group. The structure is one-dimensional and consists of twelve tellurium molecules; four Te4Br clusters; and two NbOBr4 ribbons oriented in the (1, 0, 0) direction. In each Te4Br cluster, there are two inequivalent Te+0.57+ sites. In the first Te+0.57+ site, Te+0.57+ is bonded in a single-bond geometry to one Br1- atom. The Te–Br bond length is 3.46 Å. In the second Te+0.57+ site, Te+0.57+ is bonded in a single-bond geometry to one Br1- atom. The Te–Br bond length is 3.38 Å. Br1- is bonded in a 2-coordinate geometry to four Te+0.57+ atoms. In each NbOBr4 ribbon, Nb3+ is bonded to two equivalent O2- and four Br1- atoms to form distorted corner-sharing NbBr4O2 octahedra. The corner-sharing octahedral tilt angles are 0°. There are one shorter (1.78 Å) and one longer (2.32 Å) Nb–O bond lengths. There are two shorter (2.57 Å) and two longer (2.58 Å) Nb–Br bond lengths. O2- is bonded in a distorted linear geometry to two equivalent Nb3+ atoms. There are two inequivalent Br1- sites. In the first Br1- site, Br1- is bonded in a single-bond geometry to one Nb3+ atom. In the second Br1- site, Br1- is bonded in a single-bond geometry to one Nb3+ atom.