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(NdSb)2CdSb crystallizes in the tetragonal P4/mmm space group. The structure is zero-dimensional and consists of one antimony molecule, one cadmium molecule, and two NdSb clusters. In each NdSb cluster, Nd3+ is bonded in a single-bond geometry to one Sb+2.67- atom. The Nd–Sb bond length is 2.72 Å. Sb+2.67- is bonded in a single-bond geometry to one Nd3+ atom.
Nd2CdSb4 crystallizes in the tetragonal P-4m2 space group. The structure is three-dimensional. Nd3+ is bonded in a 8-coordinate geometry to eight Sb2- atoms. There are four shorter (3.25 Å) and four longer (3.35 Å) Nd–Sb bond lengths. Cd2+ is bonded to four equivalent Sb2- atoms to form corner-sharing CdSb4 tetrahedra. All Cd–Sb bond lengths are 2.89 Å. There are two inequivalent Sb2- sites. In the first Sb2- site, Sb2- is bonded to four equivalent Nd3+ and two equivalent Cd2+ atoms to form a mixture of distorted face, edge, and corner-sharing SbNd4Cd2 pentagonal pyramids. In the second Sb2- site, Sb2- is bonded in a 8-coordinate geometry to four equivalent Nd3+ and four equivalent Sb2- atoms. All Sb–Sb bond lengths are 3.10 Å.