Materials Data on BaNb2V2O11 by Materials Project
BaNb2V2O11 crystallizes in the trigonal R-3m space group. The structure is three-dimensional. Ba2+ is bonded to twelve O2- atoms to form BaO12 cuboctahedra that share edges with six equivalent BaO12 cuboctahedra, edges with six equivalent VO4 tetrahedra, and faces with two equivalent NbO6 octahedra. There are six shorter (2.90 Å) and six longer (3.28 Å) Ba–O bond lengths. Nb5+ is bonded to six O2- atoms to form NbO6 octahedra that share corners with three equivalent NbO6 octahedra, corners with three equivalent VO4 tetrahedra, and a faceface with one BaO12 cuboctahedra. The corner-sharing octahedral tilt angles are 0°. There are three shorter (1.93 Å) and three longer (2.08 Å) Nb–O bond lengths. V5+ is bonded to four O2- atoms to form VO4 tetrahedra that share corners with three equivalent NbO6 octahedra and edges with three equivalent BaO12 cuboctahedra. The corner-sharing octahedral tilt angles are 24°. There is one shorter (1.68 Å) and three longer (1.76 Å) V–O bond length. There are three inequivalent O2- sites. In the first O2- site, O2- is bonded in a linear geometry to two equivalent Nb5+ atoms. In the second O2- site, O2- is bonded in a distorted bent 150 degrees geometry to one Ba2+, one Nb5+, and one V5+ atom. In the third O2- site, O2- is bonded in a single-bond geometry to three equivalent Ba2+ and one V5+ atom.