Dynamics of the reaction of C{sub 3}(a{sup 3}Π{sub u}) radicals with C{sub 2}H{sub 2}: A new source for the formation of C{sub 5}H
The reaction C{sub 3}(a{sup 3}Π{sub u}) + C{sub 2}H{sub 2} → C{sub 5}H + H was investigated at collision energy 10.9 kcal mol{sup −1} that is less than the enthalpy of ground-state reaction C{sub 3}(X{sup 1}Σ{sub g}{sup +}) + C{sub 2}H{sub 2} → C{sub 5}H + H. C{sub 3}(a{sup 3}Π{sub u}) radicals were synthesized from 1% C{sub 4}F{sub 6}/He by pulsed high-voltage discharge. The title reaction was conducted in a crossed molecular-beam apparatus equipped with a quadrupole-mass filter. Product C{sub 5}H was interrogated with time-of-flight spectroscopy and synchrotron vacuum-ultraviolet ionization. Reactant C{sub 3}(a{sup 3}Π{sub u}) and product C{sub 5}H were identified using photoionization spectroscopy. The ionization thresholds of C{sub 3}(X{sup 1}Σ{sub g}{sup +}) and C{sub 3}(a{sup 3}Π{sub u}) are determined as 11.6 ± 0.2 eV and 10.0 ± 0.2 eV, respectively. The C{sub 5}H product is identified as linear pentynylidyne that has an ionization energy 8.4 ± 0.2 eV. The title reaction releases translational energy 10.6 kcal mol{sup −1} in average and has an isotropic product angular distribution. The quantum-chemical calculation indicates that the C{sub 3}(a{sup 3}Π{sub u}) radical attacks one of the carbon atoms of C{sub 2}H{sub 2} and subsequently a hydrogen atom is ejected to form C{sub 5}H + H, in good agreement with the experimental observation. As far as we are aware, the C{sub 3}(a{sup 3}Π{sub u}) + C{sub 2}H{sub 2} reaction is investigated for the first time. This work gives an implication for the formation of C{sub 5}H from the C{sub 3}(a{sup 3}Π{sub u}) + C{sub 2}H{sub 2} reaction occurring in a combustion or discharge process of C{sub 2}H{sub 2}.